NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.7

### NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.7

**NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.7**

Ex 2.7 Class 7 Maths Question 1.

Find:

(i) 0.4 ÷ 2

(ii) 0.35 ÷ 5

(iii) 2.48 ÷ 4

(iv) 65.4 ÷ 6

(v) 651.2 ÷ 4

(vi) 14.49 ÷ 7

(vii) 3.96 ÷ 4

(viii) 0.80 ÷ 5

Solution:

Ex 2.7 Class 7 Maths Question 2.

Find:

(i) 4.8 ÷ 10

(ii) 52.5 ÷ 10

(iii) 0.7 ÷ 10

(iv) 33.1 ÷ 10

(v) 272.23 ÷ 10

(vi) 0.56 ÷ 10

(vii) 3.97 ÷10

Solution:

(i) 4.8 ÷ 10 = 0.48 (Shifting the decimal point to the left by 1 place)

(ii) 52.5 ÷ 10 = 5.25 (Shifting the decimal point to the left by 1 place)

(iii) 0.7 ÷ 10 = 0.07 (Shifting the decimal point to the left by 1 place)

(iv) 33.1 ÷ 10 = 3.31 (Shifting the decimal point to the left by 1 place)

(v) 272.23 ÷ 10 = 27.223 (Shifting the decimal point to the left by 1 place)

(vi) 0.56 4- 10 = 0.056(Shifting the decimal point to the left by 1 place)

(vii) 3.97 ÷ 10 = 0.397(Shifting the decimal point to the left by 1 place)

Ex 2.7 Class 7 Maths Question 3.

Find:

(i) 2.7 ÷ 100

(ii) 0.3 ÷ 100

(iii) 0.78 ÷ 100

(iv) 432.6 ÷ 100

(v) 23.6 ÷ 100

(vi) 98.53 ÷ 100

Solution:

Solution:

(i) 2.7 ÷ 100 = 0.027(Shifting the decimal point to the left by 2 places)

(ii) 0.3 ÷ 100 = 0.003(Shifting the decimal point to the left by 2 places)

(iii) 0.78 ÷ 100 = 0.0078 (Shifting the decimal point to the left by 2 places)

(iv) 432.6 ÷ 100 = 4.326 (Shifting the decimal point to the left by 2 places)

(v) 23.6 ÷ 100 = 0.236 (Shifting the decimal point to the left by 2 places)

(vi) 98.53 ÷ 100 = 0.9853 (Shifting the decimal point to the left by 2 places)

Ex 2.7 Class 7 Maths Question 4.

Find:

(i) 7.9 ÷ 1000

(ii) 26.3 ÷ 1000

(iii) 38.53 ÷ 1000

(iv) 128.9 ÷ 1000

(v) 0.5 ÷ 1000

Solution:

(i) 7.9 ÷ 1000 = 0.0079 (Shifting the decimal point to the left by 3 places)

(ii) 26.3 ÷ 1000 = 0.0263 (Shifting the decimal point to the left by 3 places)

(iii) 38.53 ÷ 1000 = 0.03853 (Shifting the decimal point to the left by 3 places)

(iv) 128.9 ÷ 1000 = 0.1289 (Shifting the decimal point to the left by 3 places)

(v) 0.5 ÷ 1000 = 0.0005 (Shifting the decimal point to the left by 3 places)

Ex 2.7 Class 7 Maths Question 5.

Find:

(i) 7 ÷ 3.5

(ii) 36 ÷ 0 .2

(iii) 3.25 ÷ 0.5

(iv) 30.94 ÷ 0.7

(v) 0.5 ÷ 0.25

(vi) 7.75 ÷ 0.25

(vii) 76.5 ÷ 0.15

(viii) 37.8 ÷ 1.4

(ix) 2.73 ÷ 1.3

Solution:

Ex 2.7 Class 7 Maths Question 6.

A vehicle covers a distance of 43.2 km in 2.4 litres of Petrol. How much distance will it cover in one litre of petrol?

Solution:

2.4 litres of petrol is required to cover 43.2 km distance

∴ 1 litre of petrol will be required to cover 43.2

Hence, the required distance = 18 km